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3x^2-(58/8)x+2=0
Domain of the equation: 8)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3x^2-(+58/8)x+2=0
We multiply parentheses
3x^2-58x^2+2=0
We add all the numbers together, and all the variables
-55x^2+2=0
a = -55; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-55)·2
Δ = 440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{440}=\sqrt{4*110}=\sqrt{4}*\sqrt{110}=2\sqrt{110}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{110}}{2*-55}=\frac{0-2\sqrt{110}}{-110} =-\frac{2\sqrt{110}}{-110} =-\frac{\sqrt{110}}{-55} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{110}}{2*-55}=\frac{0+2\sqrt{110}}{-110} =\frac{2\sqrt{110}}{-110} =\frac{\sqrt{110}}{-55} $
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